(c^2-6)(2c^2+3c-1)=0

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Solution for (c^2-6)(2c^2+3c-1)=0 equation:


Simplifying
(c2 + -6)(2c2 + 3c + -1) = 0

Reorder the terms:
(-6 + c2)(2c2 + 3c + -1) = 0

Reorder the terms:
(-6 + c2)(-1 + 3c + 2c2) = 0

Multiply (-6 + c2) * (-1 + 3c + 2c2)
(-6(-1 + 3c + 2c2) + c2(-1 + 3c + 2c2)) = 0
((-1 * -6 + 3c * -6 + 2c2 * -6) + c2(-1 + 3c + 2c2)) = 0
((6 + -18c + -12c2) + c2(-1 + 3c + 2c2)) = 0
(6 + -18c + -12c2 + (-1 * c2 + 3c * c2 + 2c2 * c2)) = 0
(6 + -18c + -12c2 + (-1c2 + 3c3 + 2c4)) = 0

Combine like terms: -12c2 + -1c2 = -13c2
(6 + -18c + -13c2 + 3c3 + 2c4) = 0

Solving
6 + -18c + -13c2 + 3c3 + 2c4 = 0

Solving for variable 'c'.

The solution to this equation could not be determined.

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